Not anything major. It's just syntactic sugar for "\x -> x == 10". | Hacker News

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		tome on Oct 26, 2016 \| parent \| context \| favorite \| on: Server APIs Project Not anything major. It's just syntactic sugar for "\x -> x == 10".

seanparsons on Oct 26, 2016 [–]

How is it syntactic sugar? It's just applying "10" to the first parameter of "==".

dllthomas on Oct 27, 2016 | [–]

Without parentheses, == is infix. (== 10) is an "operator section", and applies 10 to the second parameter of ==. (10 ==) would be the first parameter.

seanparsons on Oct 27, 2016 | | [–]

Ah yes, very true.

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